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Plot y=sinxa n dy=sin2xdot...

Plot `y=sinxa n dy=sin2xdot`

Text Solution

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We have `y=sin2x.`
Since the period of `y=sin2x" is "(2pi)/(2)=pi`, the graph completes its one cycle in the interval of length `pi`.
In any interval of length `pi`, sin 2x takes all its values, which are [-1,1].
So graph of `y=sin2x" for "x in[0,pi]` is as follows.

Thus, the graph of `y=sinx` is compressed by 2 units horizontally.
In `[0,2pi],y=sin2x` completes its two cycles.
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