The range of the function `f` defined by `f(x)=[1/(sin{x})]` (where [.] and `{dot},` respectively, denote the greatest integer and the fractional part functions) is

Solve : [x]^(2)=x+2{x}, where [.] and {.} denote the greatest integer and the fractional part functions, respectively.

Solve 2[x]=x+{x},w h r e[]a n d{} denote the greatest integer function and the fractional part function, respectively.

Solve : 4{x}= x+ [x] (where [*] denotes the greatest integer function and {*} denotes the fractional part function.

Find the range of the function f(x)=(1)/(2+sin3x) .

The total number of solutions of [x]^2=x+2{x}, where [.] and {.} denote the greatest integer and the fractional part functions, respectively, is equal to: 2 (b) 4 (c) 6 (d) none of these

In the question, [x]a n d{x} represent the greatest integer function and the fractional part function, respectively. Solve: [x]^2-5[x]+6=0.

Solve (x-2)[x]={x}-1, (where [x]a n d{x} denote the greatest integer function less than or equal to x and the fractional part function, respectively).

If f(x) = [x] , 0<= {x} < 0.5 and f(x) = [x]+1 , 0.5<{x}<1 then prove that f (x) = -f(-x) (where[.] and{.} represent the greatest integer function and the fractional part function, respectively).

lim_(x-(pi)/(2)) [([sinx]-[cosx]+1)/(3)]= (where [.] denotes the greatest integer integer function)

The number of points of discontinuity of f(x)=[2x]^(2)-{2x}^(2) (where [ ] denotes the greatest integer function and { } is fractional part of x) in the interval (-2,2) , is