Find the sum of the series `1/(3^2+1)+1/(4^2+2)+1/(5^2+3)+1/(6^2+4)+oo`

Find the sum of the following series: 1/2+1/(3^2)+1/(2^3)+1/(3^4)+1/(2^5)+1/(3^6)+oo

Find the sum to n terms of the series: 1/(1+1^2+1^4)+1/(1+2^2+2^4)+1/(1+3^2+3^4)+

The sum of the series 1^(2) + 3^(2) + 5^(2) + ......+n'

Let S denote sum of the series 3/(2^3)+4/(2^4 .3)+5/(2^6 .3)+6/(2^7 .5)+oo Then the value of S^(-1) is __________.

The sum of the series 1 + (1)/(3^(2)) + (1 *4)/(1*2) (1)/(3^(4))+( 1 * 4 * 7)/(1 *2*3)(1)/(3^(6)) + ..., is

Find the sum of the series (2^(3)-1)+(4^(3)-3^(3))+(6^(3)-15^(3))+… to n terms

Find the sum of the series (2^(3)-1)+(4^(3)-3^(3))+(6^(3)-15^(3))+… to 8 terms

The sum of series 1/2! + 1/4! + 1/6! + …….. is

Find the sum to n terms of the series 1//(1xx2)+1//(2xx3)+1//(3xx4)++1//n(n+1)dot

Find the sum to n terms of the series 1^2+2^2+3^2-4^2+5^2-6^2+. . . .