The value of `("lim")_(xvecoo)[3sqrt((n+1)^2) -3sqrt((n-1)^2 ))]` is_____

Evaluate: ("lim")_(xvecoo)(sqrt(3x^2-1)-sqrt(2x^2-1))/(4x+3)

The value of ("lim")_(xto2)(sqrt(1+sqrt(2+x))-sqrt(3))/(x-2)i s (a) 1/(8sqrt(3)) (b) 1/(4sqrt(3)) (c) 0 (d) none of these

The value of ("lim")_(nvecoo)sum_(r=1)^(4n)(sqrt(n))/(sqrt(r)(3sqrt(r)+sqrt(n))^2) is equal to 1/(35) (b) 1/4 (c) 1/(10) (d) 1/5

The value of lim_(ntooo) [(1+2+3+...+n)/n^2] is

The value of (lim)_(xvecoo)(tan^(-1)x))) is equal to (a)-1 (b) pi/2 (c) -1/(sqrt(2)) (d) 1/(sqrt(2))

The value of lim_(nto0) [(1+2+3+...+n)/n^2] is

The value of lim_(nrarroo) ((n^(2)-n+1)/(n^(2)-n-1))^(n(n-1) is

Evaluate: ("lim")_(nvecoo)(1/(sqrt(4n^2-1))+1/(sqrt(4n^2-2^2))++1/(sqrt(3n^2)))

The value of lim_(ntooo) [(1+2+3+...+n)/(n^2+5n+2)] is

Evaluate: ("lim")_(xvecoo)sin^n((2pin)/(3n+1)),n in Ndot