`lim_(x->-oo)(x^2*tan(1/x))/(sqrt(8x^2+7x+1))` is

lim_(xtooo) (x^(2)"tan"(1)/(x))/(sqrt(8x^(2)+7x+1)) is equal to

lim_(x->oo) (e^(1/x^2)-1)/(2tan^-1(x^2)-pi) is equal to (a) 1 (b) -1 (c) 1/2 (d) -1/2

lim_(xto oo)(sqrt(4x^(2)+2x+1)-sqrt(4x^(2)+1)) is

lim_(xto0)(sqrt(1-x)-1)/x^(2)

(a ) Evaluate : lim_(x to0) (sqrt(x^(2)+1)-1)/(sqrt(x^(2)+16)-4)

lim_(x->oo)[sqrt(x+sqrt(x+sqrt(x)))-sqrt(x)] is equal to (a)0 (b) 1/2 (c) log 2 (d) e^4

lim_(xtooo)(1+1/x)^(7x)

Evaluate lim_(xto1)(sqrt(x^(2)-1)+sqrt(x-1))/(sqrt(x^(2)-1)) if xgt1 .

if Delta (x) = |{:(tan x,,tan (x+h),,tan(x+2h)),(tan(x+2h),,tan x,,tan(x+h)),(tan(x+h),,tan(x+2h),,tanx):}|, " then " The value of lim_(h to 0) .(Delta (pi//3))/(sqrt(3)h^(2)) " is "

lim_(x->oo)((2x+1)^(40)(4x-1)^5)/((2x+3)^(45)) is equal to (a)16 (b) 24 (c) 32 (d) 8