If `omega` is a cube root of unity and `(omega-1)^7=A+Bomega` then find the values of A` and `B`

Find the cube roots of unity.

If omega ne 1 is a cubic root of unit and (1 + omega)^(7) = A + B omega , then (A, B) equals

If omega(!= 1) be an imaginary cube root of unity and (1+omega^2)=(1+omega^4), then the least positive value of n is (a) 2 (b) 3 (c) 5 (d) 6

If omega is a non real cube root of unity, then (a+b)(a+b omega)(a+b omega^2)=

If omega is a cube root of unity, then find the value of the following: (1+omega-omega^2)(1-omega+omega^2)

If omega is an imaginary cube root of unity, then (1+omega-omega^2)^7 is equal to (a) 128omega (b) -128omega (c) 128omega^2 (d) -128omega^2

a ,b , c are integers, not all simultaneously equal, and omega is cube root of unity (omega!=1) , then minimum value of |a+bomega+comega^2| is 0 b. 1 c. (sqrt(3))/2 d. 1/2