In the Argands plane what is the locus of `z(!=1)` such that `a rg{3/2((2z^2-5z+3)/(2z^2-z-2))}=(2pi)/3dot`

If |z-1|=2 then the locus of z is

Represents the variable complex number z . Find the locus of P if arg((z-1)/(z+3))=(pi)/(2) .

If z_1, z_2, z_3, z_4 are the affixes of four point in the Argand plane, z is the affix of a point such that |z-z_1|=|z-z_2|=|z-z_3|=|z-z_4| , then z_1, z_2, z_3, z_4 are

Solve for z : z^2-(3-2i)z=(5i-5)dot

If z= x+iy find the locus of z if |2z+1| = 2 .

If |z+3|^(2)-|z-3|^(2)=8 then the locus of z is

If |z-z_(1)|=|z-z_(2)| then the locus of z is :

On the Argand plane z_1, z_2a n dz_3 are respectively, the vertices of an isosceles triangle A B C with A C=B C and equal angles are thetadot If z_4 is the incenter of the triangle, then prove that (z_2-z_1)(z_3-z_1)=(1+sectheta)(z_4-z_1)^2dot

If z^(2)+z+1=0 , where z is a complex number, then the value of (z+(1)/(z))^(2)+(z^(2)+(1)/(z^2))^(2)+(z^(3)+(1)/(z^3))^(2)+"……"+(z^(6)+(1)/(z^6))^(2) is

Locate the region in the Argand plane determined by z^2+ z ^2+2|z^2|<(8i( z -z)) .