`(costheta + isintheta)^4/(sintheta + icostheta)^5` is equal to.

3(sintheta-costheta)^4+6(sintheta +costheta)^2+4(sin^6theta+cos^6theta) is equal to 11 (b) 12 (c) 13 (d) 14

(sintheta+sin2theta)/(1+costheta+cos2theta)

If 5tantheta=4, then (5sintheta-3costheta)/(5sintheta+2costheta) is equal to 0 (b) 1 (c) 1/6 (d) 6

Prove that [{:(costheta,-sintheta),(sintheta,costheta):}] is orthogonal.

If costheta[(costheata, sintheta), (-sintheta, costheta)]+sintheta[(x, -costheta), (costheta, x)]=I_(2) . Find x.

costheta -sintheta -cottheta +1=0

If (costheta +isintheta)(cos2theta +isin2theta).....(cosntheta + isinntheta) = 1 then the value of theta is:

choose the correct pair of statement : (i) (costheta+isintheta)^(n)=cosntheta+isinntheta , x is an integer (ii) (sintheta+icostheta)^(n)=sinntheta+icosthetantheta , n is an integer (iii) If z=costheta+isintheta , then z^(-1)=costheta-isintheta (iv)(z+barz)/(2)=Re(z)

If x=(2sintheta)/(1+costheta+sintheta),t h e n(1-costheta+sintheta)/(1+sintheta) is equal to 1+x (b) 1-x (c) x (d) 1/x