Solve the equation |z|=z+1+2idot...

Solve the equation `|z|=z+1+2idot`

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Let z=x+iy. Then, `∣z∣=x^2+y^2` and z+1+2i=(x+1)+i(y+2).= `sqrt(x^2+y^2) =(x+1)+i(y+2)`
`sqrt(x^2+y^2) =x+1 and y+2=0`
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