The first three terms in the expansion of `(1+a x)^n(n!=0)` are `1,6xa n d16 x^2dot` Then find the value of `aa n dndot`

Find the constant term in the expansion of (x-1//x)^6dot

If the middle term in the expansion of (x^2+1//x)^n is 924 x^6, then find the value of ndot

The sum of the coefficients of the first three terms in the expansion of (x - 3/x^(2))^(n)x != 0 ,m being a natural number, is 559. Find the term of the expansion containing x^(3) .

If the three consecutive coefficients in the expansion of (1+x)^n are 28, 56, and 70, then the value of n is.

In the expansion of (1+x)^n , 7th and 8th terms are equal. Find the value of (7//x+6)^2 .

If the constant term in the binomial expansion of (x^2-1/x)^n ,n in N is 15, then the value of n is equal to.

The coefficients of three consecutive terms in the expansion of (1 + a)^n are are in the ratio 1: 7: 42 Find n.

The coefficient of x^(n) in expansion of (1 + x)(1 - x)^(n) is