The number of triangles that can be formed with 10 points as vertices `n` of them being collinear, is 110. Then `n` is a. `3` b. `4` c. `5` d. `6`

The number of straight lines that can be formed by joining 20 points of which 4 points are collinear is

The number of triangles which can be formed by using the vertices of a regular polygon of (n + 3) sides is 220. Then n =

Let T_(n) denote the number of triangles which can be formed by using the vertices of a regular polygon of n sides. If T_(n+1)-T_(n)=28 Then n =

Deterime whether the points are vertices of a right triangle A(-3,-4),B(2,6) and C(-6,10).

Can the number 6^n , n being a natural number, end with the digit 5? Give reason.

If b=3,c=4,a n dB=pi/3, then find the number of triangles that can be constructed.

Let T_(n) denote the number of triangles which can be formed by using the vertices of a regular polygon of n sides. If T_(n + 1) - T_(n) = 36 , then n is equal to

In a plane are 10 points are there out of which 4 points are collinear, then the number of triangles formed is

There are 8 points in a plane, no three of them are collinear .The number of triangles that can be formed is: