Home
Class 11
MATHS
2m white counters and 2n red counters ar...

`2m` white counters and `2n` red counters are arranged in a straight line with `(m+n)` counters on each side of central mark. The number of ways of arranging the counters, so that the arrangements are symmetrical with respect to the central mark is `(A)` `.^(m+n)C_m` `(B)` `.^(2m+2n)C_(2m)` `(C)` `1/2 ((m+n)!)/(m! n!)` `(D)` None of these

Promotional Banner

Similar Questions

Explore conceptually related problems

The number of ways of arranging m positive and n(lt m+1) negative signs in a row so that no two are together is a)^m+1p_n b ^n+1p_m c)^m+1C_n d)^n+1c_m

The number of ordered pairs of positive integers (m,n) satisfying m le 2n le 60 , n le 2m le 60 is

m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

The number of ways in which we can distribute m n students equally among m sections is given by a. ((m n !))/(n !) b. ((m n)!)/((n !)^m) c. ((m n)!)/(m ! n !) d. (m n)^m

A rectangle with sides of lengths (2n-1) and (2m-1) units is divided into squares of unit length. The number of rectangles which can be formed with sides of odd length, is (a) m^2n^2 (b) mn(m+1)(n+1) (c) 4^(m+n-1) (d) non of these

The integral value of m for which the root of the equation m x^2+(2m-1)x+(m-2)=0 are rational are given by the expression [where n is integer] (A) n^2 (B) n(n+2) (C) n(n+1) (D) none of these

If sum of m terms is n and sum of n terms is m, then show that the sum of (m + n) terms is -(m + n).

If x^m occurs in the expansion (x+1//x^2)^ 2n then the coefficient of x^m is ((2n)!)/((m)!(2n-m)!) b. ((2n)!3!3!)/((2n-m)!) c. ((2n)!)/(((2n-m)/3)!((4n+m)/3)!) d. none of these

A coin is tossed (m+n) times with m>n. Show that the probability of getting m consecutive heads is (n+2)/2^(m+1)