Home
Class 11
MATHS
Two players P1a n dP2 play a series ...

Two players `P_1a n dP_2` play a series of `2n` games. Each game can result in either a win or a loss for `P_1dot` the total number of ways in which `P_1` can win the series of these games is equal to a. `1/2(2^(2n)-^ "^(2n)C_n)` b. `1/2(2^(2n)-2xx^"^(2n)C_n)` c. `1/2(2^n-^"^(2n)C_n)` d. `1/2(2^n-2xx^"^(2n)C_n)`

Promotional Banner

Similar Questions

Explore conceptually related problems

The total number of ways in which 2n persons can be divided into n couples is a. (2n !)/(n ! n !) b. (2n !)/((2!)^3) c. (2n !)/(n !(2!)^n) d. none of these

In a game a coin is tossed 2n+m times and a player wins if he does not get any two consecutive outcomes same for at least 2n times in a row. The probability that player wins the game is a. (m+2)/(2^(2n)+1) b. (2n+2)/(2^(2n)) c. (2n+2)/(2^(2n+1)) d. (m+2)/(2^(2n))

If sinx+cos e cx=2, then sin^n x+cos e c^n x is equal to 2 (b) 2^n (c) 2^(n-1) (d) 2^(n-2)

If n in N >1 , then the sum of real part of roots of z^n=(z+1)^n is equal to n/2 b. ((n-1))/2 c. n/2 d. ((1-n))/2

If tanx=ntany ,n in R^+, then the maximum value of sec^2(x-y) is equal to (a) ((n+1)^2)/(2n) (b) ((n+1)^2)/n (c) ((n+1)^2)/2 (d) ((n+1)^2)/(4n)

A coin is tossed 2n times. The chance that the number of times one gets head is not equal to the number of times one gets tails is ((2n !))/((n !)^2)(1/2)^(2n) b. 1-((2n !))/((n !)^2) c. 1-((2n !))/((n !)^2)1/(4^n)^ d. none of these

Find the sum 1.^(n)C_(0) + 3 .^(n)C_(1) + 5.^(n)C_(2) + "….." + (2n+1).^(n)C_(n) .

("lim")_(xto0)((2^m+x)^(1/m)-(2^n+x)^(1/n))/x is equal t o (a) 2 (1/(m2^m)-1/(n2^n))' (b) (1/(m2^m)+1/(n2^n)) (c) 1/(m2^(-m))-1/(n2^(-n)) (d) 1/(m2^(-m))+1/(n2^(-n))

In a n- sided regular polygon, the probability that the two diagonal chosen at random will intersect inside the polygon is (2^n C_2)/(^(^(n C_(2-n)))C_2) b. (^(n(n-1))C_2)/(^(^(n C_(2-n)))C_2) c. (^n C_4)/(^(^(n C_(2-n)))C_2) d. none of these

Prove that .^(n)C_(0) - ^(n)C_(1) + .^(n)C_(2)- ^(n)C_(3) + "…" + (-1)^(r) + .^(n)C_(r) + "…" = (-1)^(r ) xx .^(n-1)C_(r ) .