If `a = underset(55 "times")underbrace(111.....1), b= 1+10+10^(2)+10^(3)+10^(4) and c=1+10^(5)+10^(10)+……+10^(50)` then

Write (a) 9.87 xx 10^(9), (b) 4.134 xx 10^(-4) and (c) 1.432 xx 10^(-9) in decimal form.

Let a=111 1(55d igi t s),b=1+10+1=^2++10^4,c=1+10^5+10^(10)+10^(15)++10^(50), then a=b+c b. a=b c c. b=a c d. c=a b

Simplify : (1.02xx10^10) xx(1.20xx10^(-3))

Find the sum ^10 C_1+^(10)C_3+^(10)C_5+^(10)C_7+^(10)C_9dot

The length of a rod is exactly 1 m when measured at rest . What will be its length when it moves at a speed of (a) 3 xx 10^(5)m s ^(-1) (b) 3 xx 10^(6) m s^(-1) and ( c) 3 xx 10^(7) m s ^(-1) ?

Simplify: (i) (2.75 xx 10^(7))+(1.23 xx 10^(8)) (ii) (1.598 xx 10^(17)) -(4.58 xx 10^(15)) (iii) (1.02 xx 10^(10)) xx (1.20 xx 10^(-3)) (iv) (8.41 xx 10^(4)) divide (4.3 xx 10^(5))