If `(log)_3 2,(log)_3(2^x-5)a n d(log)_3(2^x-7/2)` are in arithmetic progression, determine the value of `xdot`

If log_(3)^(2) , log_(3)(2^(x) - 5) and log(2^(x) - 7/2) are in A.P then the value is x is

Solve: (log)_3(2x^2+6x-5)>1

Solve (log)_2(3x-2)=(log)_(1/2)x

Solve (log)_4 8+(log)_4(x+3)-(log)_4(x-1)=2.

Solve (log)_3(x-2)lt=2.

Solve (log)_(2x)2+(log)_4 2x=-3//2.

Solve: (log)_2(4.3^x-6)-(log)_2(9^x-6)=1.

If (log)_2y=xa n d(log)_3z=x , find 72^x in terms of yand zdot

Let f(x)=(log)_2(log)_3(log)_4(log)_5(s in x+a^2)dot Find the set of values of a for which the domain of f(x)i sRdot

Arrange (log)_2 5,(log)_(0. 5)5,(log)_7 5,(log)_3 5 in decreasing order.