The third term of a geometric progression is 4. Then find the product of the first five terms.

The third term of a geometric progression is 4. The product of the first five terms is (1982, 28M) 4^3 (b) 4^5 (c) 4^4 (d) None of these

The first term of an arithmetic progression is 1 and the sum of the first nine terms equal to 369 . The first and the ninth term of a geometric progression coincide with the first and the ninth term of the arithmetic progression. Find the seventh term of the geometric progression.

If the product of the 4^(th), 5^(th) and 6^(th) terms of a geometric progression is 4096 and if the product of the 5^(th), 6^(th) and 7^(th) - terms of it is 32768, find the sum of first 8 terms of the geometric progression. For any two positive numbers, the three means AM, GM and HM are in geometric progression.

The 4th term of a geometic progression is 2/3 and the seventh term is 16/81 . Find the geometic series.

Find the sum of the first 20 terms of the arithmetic progression having the sum of first ten terms as 52 and the sum of the first 15 terms as 77.

If the third term of a G.P is P. Then the Product of the first 5 terms of the G.P is

Find four numbers forming a geometric progression in which the third term is greater than the first term by 9, and the second term is greater than the 4^("th") by 18.

The product of three consecuitive terms of a Geometric Progression is 343 and their sum is (91)/(3) . Find the three terms .