If `x=a(theta+sintheta), y=a(1-costheta)` then prove that at `theta=pi/2, y''=1/a`.

If x= a (theta+ sin theta), y =a ( 1- cos theta) then prove that at theta = (pi)/(2), y'' = (1)/(a) .

If x=a(theta+sintheta), y=a(1+costheta) " then " (dy)/(dx) is

(sintheta+sin2theta)/(1+costheta+cos2theta)

Find the length of normal to the curve x=a(theta+sintheta),y=a(1-costheta) at theta=pi/2dot

Prove that (sintheta +sin2theta)/(1+costheta +cos2theta)=tantheta

If sintheta +costheta =1 then sin^6 theta +cos^6 theta is:

If sintheta=costheta , then the value of ' theta ' is ___.

If sintheta(1+sin^(2)theta)=cos^(2)theta , then prove that cos^(6)theta-4cos^(2)theta+8cos^(2)theta=4

If xsin^(3) theta +y cos^(3) theta=sin theta cos theta and x sin theta =y cos theta , then prove that x^(2)+y^(2)=1 .