Find the equation of the normal to the curve `y=(1+x)^y+sin^(-1)(sin^2x) at `x=0.`

The equation of the normal to the curve y=x^3 , at (1,1) is

The equation of the normal to the curve y = x^(3) " at" (1, 1) is

Find the equation of tangent to the curve y=sin^(-1)(2x)/(1+x^2)a tx=sqrt(3)

Find the equation of tangent and normal to the curve y = x^(2) + 3x + 2 at (0, 2)

The slope of the normal to the curve y = 2x^(2) + 3 sin x at x = 0 is

Find the equation of the normals to the curve y = x^(3) + 2x + 6 which are parallel to the line x + 14y + 4 = 0.

Find the equations of the tangent and normal to the curve x^(2/3)+y^((2)/(3))=2 at (1,1).

Find the equations of tangent and normal to the curve y=x^(2) - 2x -3 at the point (2, 3)

Find the equations of tangent and normal to the curve y=x^(2)+3x-2 at the point (1, 2). .