If `^n+1C_(r+1) : ^n C_r : ^(n-1)C_(r-1)=11 :6:3,` then `n r =`

In .^(2n)C_(3) :.^(n)C_(3) = 11 : 1 then n is

.^((n-1)C_(r) + ^((n-1)) C_((r-1)) is

If ^n C_r=84 ,^n C_(r-1)=36 ,a n d^n C_(r+1)=126 , then find the value of ndot

If ""^(2n)C_(3) : ""^(n) C_(3)= 11 : 1 then n is

If ^n P_r=^n P_(r+1)a n d^n C_r=^n C_(r-1,) then the value of n+r is.

If .^(n)C_(r-1)=36, .^(n)C_(r)=84 and .^(n)C_(r+1)=126 , find n and r.

Verify the property ""^(n)C_(r)=n/r ""^(n-1)C_(r-1) where n=6 and r=3.

If sum_(r=0)^(n){("^(n)C_(r-1))/('^(n)C_(r )+^(n)C_(r-1))}^(3)=(25)/(24) , then n is equal to

The roots of the equation |^x C_r^(n-1)C_r^(n-1)C_(r-1)^(x+1)C_r^n C_r^n C_(r-1)^(x+2)C_r^(n+1)C_r^(n+1)C_(r-1)|=0 are x=n b. x=n+1 c. x=n-1 d. x=n-2

If ""^(n)P_r = ""^(n)P_(r-1) and ""^(n)C_(r) = ""^(n)C_(r-1) , find the values of n and r.