Leg `f(x)=x^4-4x^3+6x^2-4x+1.` Then, `f` increase on `[1,oo]` `f` decreases on `[1,oo]` `f` has a minimum at `x=1` `f` has neither maximum nor minimum

Let f(x)={x+2,-|lt=x<0 1,x=0x/2,0

f'(x) = x^(2) - 5x + 4 then f(x) is decreasing in

Consider the function f:(-oo,oo)vec(-oo,oo) defined by f(x)=(x^2+a)/(x^2+a),a >0, which of the following is not true? maximum value of f is not attained even though f is bounded. f(x) is increasing on (0,oo) and has minimum at ,=0 f(x) is decreasing on (-oo,0) and has minimum at x=0. f(x) is increasing on (-oo,oo) and has neither a local maximum nor a local minimum at x=0.

If f(x)=2x+cot^(-1)x+log(sqrt(1+x^2)-x) then f(x) (a)increase in (0,oo) (b)decrease in [0,oo] (c)neither increases nor decreases in [0,oo] (d)increase in (-oo,oo)

Prove that f(x) = x^(2) -x + 1 is neither encreasing nor decreasing in [0,1]

Let f(x)=|x^2-3x-4|,-1lt=xlt=4 Then f(x) is monotonically increasing in [-1,3/2] f(x) monotonically decreasing in (3/2,4) the maximum value of f(x)i s(25)/4 the minimum value of f(x) is 0

If f'(x)=3x^2 -4x+5" and "f(1)=3 , then find f(x) .

If f'(x) = 3x^2 - 4x + 5 and f(1) = 3 then find f(x).

Let f(x)=(x-1)^4(x-2)^n ,n in Ndot Then f(x) has a maximum at x=1 if n is odd a maximum at x=1 if n is even a minimum at x=1 if n is even a minima at x=2 if n is even

Let f be the function f(x)=cosx-(1-(x^2)/2)dot Then f(x) is an increasing function in (0,oo) f(x) is a decreasing function in (-oo,oo) f(x) is an increasing function in (-oo,oo) f(x) is a decreasing function in (-oo,0)