Let `k(x)=int((x^2+1)dx)/((x^3+3x+6)^(1/3))a n dk(-1)=1/(2^(1/3))` . Then the value of `k(-2)` is____

"Let " k(x)=int((x^(2)+1)dx)/(root(3)(x^(3)+3x+6)) " and " k(-1)=(1)/(root(3)(2)). " Then the value of " k(-2) " is "-.

Let k(x) = ((x^(2)+1))/(root(3)(x^(3)+3x+6) dx and k(-1) = 1/root (3)(2)) then the value of k(-2) is

if int (3^((1)/(x)))/(x^(2)) dx = k (3^((1)/(x))) + c , then the value of k is

If int_(2)^(a)(dx)/(x^(2)-1)=(1)/(2)"log"(3)/(2),agt1 . find the value of 'a'

Evaluate int(x^(2))/((x-1)^(3)(x+1))dx

If x=2+2^(2/3)+2^(1/3) , then the value of x^3-6x^2+6x is:

int(3x^(13)+2x^(11))/((2x^4+3x^2+1)^4)dx

Evaluate: int(dx)/(x^(1/2)+x^(1/3))

int(x+2)/((x^2+3x+3)(sqrt(x+1))).dx