Let `f(x)={x+2,-|lt=x<0 1,x=0x/2,0

Discuss the extremum of f(x)={|x^2-2|, -1lt=x

If f(x)={{:(x+2, -1 lt x lt 3), (5, x=3), (8-x, x gt 3):} , then at x=3, f'(x) is

The number of points of discontinuity of g(x)=f(f(x)) where f(x) is defined as, f(x)={1+x ,0lt=xlt=2 3-x ,2 2

Let f(x)={1+(2x)/a ,0lt=x<1 and ax ,1lt=x<2 If lim_(x->1)f(x) exists ,then a is (a) 1 (b) -1 (c) 2 (d) -2

Let f(x)={:{(x+1,x gt 0),(x-1,x lt 0):}

If X is the random variable with porbability density function f(x) given by f(x)={(x-1,1lt=xlt2),(-x+3,2lt=xlt3),(0,"otherwise"):} find (i) the distribution function F(x) (ii) P (1.5lt=X lt=2.5)

Let f(x)=|x^2-3x-4|,-1lt=xlt=4 Then f(x) is monotonically increasing in [-1,3/2] f(x) monotonically decreasing in (3/2,4) the maximum value of f(x)i s(25)/4 the minimum value of f(x) is 0

Let f(x)=|x-1|dot Then (a) f(x^2)=(f(x))^2 (b) f(x+y)=f(x)+f(y) (c) f(|x|)-|f(x)| (d) none of these

Let f(x) = max. {|x^2 - 2| x ||,| x |} then number of points where f(x) is non derivable, is :

Let f(x)=x^2-2x ,x in R ,a n dg(x)=f(f(x)-1)+f(5-f(x))dot Show that g(x)geq0AAx in Rdot