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Let F(x)=intx^[x^2+pi/6][2cos^2t.dt] for...

Let `F(x)=int_x^[x^2+pi/6][2cos^2t.dt]` for all `x in R` and `f:[0,1/2] -> [0,oo)` be a continuous function.For `a in [0,1/2]`, if F'(a)+2 is the area of the region bounded by x=0,y=0,y=f(x) and x=a, then f(0) is

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