Evaluate: `("lim")_(nvecoo)(1/(sqrt(4n^2-1))+1/(sqrt(4n^2-2^2))++1/(sqrt(3n^2)))`

Evaluate: ("lim")_(xvecoo)(sqrt(3x^2-1)-sqrt(2x^2-1))/(4x+3)

Evaluate ("lim")_(nvecoo)sum_(k=1)^nk/(n^2+k^2)

Evaluate: ("lim")_(xvecpi/4)(sqrt(2)cosx-1)/(cotx-1)

Evaluate: ("lim")_(nvecoo)(sumr=1nsqrt(r)sumr=1n1/(sqrt(r)))/(sumr=1n r)

The value of ("lim")_(nvecoo)sum_(r=1)^(4n)(sqrt(n))/(sqrt(r)(3sqrt(r)+sqrt(n))^2) is equal to 1/(35) (b) 1/4 (c) 1/(10) (d) 1/5

The value of ("lim")_(xvecoo)[3sqrt((n+1)^2) -3sqrt((n-1)^2 ))] is_____

Evaluate: ("lim")_(nvecoo)[1/(n^2)sec^2 1/(n^2)+2//n^2sec^2 4/(n^2)++1/nsec^2 1]

Evaluate lim_(xto0)(sqrt(x^2+1)-1)/(sqrt(x^2+16)-4)

lim_(xto0)(sqrt(x^(2)+1)-1)/(sqrt(x^(2)+16)-4)

Evaluate lim_(xto1)(sqrt(x^(2)-1)+sqrt(x-1))/(sqrt(x^(2)-1)) if xgt1 .