If `A=(a_("ij"))_(nxxn)` and `f` is a function, we define
`f(A)=(f(a_("ij")))_(nxxn)` Let `A=((pi//2-theta,theta),(-theta,pi//2-theta))`. Then

If A=((a_(i j)))_(nxxn) and f is a function, we define f(A)=((f(a_(i j))))_(nxxn ') Let A=(pi//2-thetatheta-thetapi//2-theta) . Then sinA is invertible b. sinA=cos A c. sinA is orthogonal d. sin(2A)=2AsinA cos A

Prove that: (cos2theta)/(1+sin2theta)=tan(pi/4-theta)

Let f(theta)=sin theta(sin theta +sin 3 theta). " Then " f(theta)

If a_(ij)=i^(2)-j and A=(a_(ij))_(2xx2) is:

If sin ((pi)/(4) cot theta) = cos ((pi)/(4) tan theta ) , then theta =

Evaluate int_(0)^((pi)/(2))(cos theta d theta)/((sin theta +2)(sin theta +3)) .

Range of f(theta)=cos^2theta(cos^2theta+1)+2sin^2theta is

If A=(a_(ij))_(2xx2) .Where a_(ij) is given by (i-2j)^(2) then A is:

Detemine the matrix A = (a_(ij))_(3 xx 2) if a_(ij) = 3i - 2j