`"I f"I_1=int_(-100)^(101)(dx)/((5+2x-2x^2)(1+e^(2-4x)))` `"and"I_2=int_(-100)^(101)(dx)/(5+2x-2x^2),t h e n(I_1)/(I_2)"i s"` (a)2 (b) `1/2` (c) 1 (d) `-1/2`

If I_1 = int_(-100)^(101) dx/((5+2x-2x^2)(1+e^(2-4x)) and I_2= int_(-100)^(101) dx/(5+2x-2x^2), then I_1/I_2 is (a) 2 (b) 1/2 (c) 1 (d) -1/2

Evaluate int_0^1(dx)/((5+2x-2x^2)(1+e^(2-4x))) dx

I=int(dx)/((2a x-x^2)

int_(1)^(2)(1/(x)-(1)/(2x^(2)))e^(2x)dx

IfI_n=int_0^pie^x(sin"x")^("n")dx ,t h e n(I_3)/(I_1)"is equal to" 3/5 (b) 1/5 (c) 1 (d) 2/5

int_(0)^(1)e^(2x)e^(e^(x) dx =)

Let I=int_1^2 (dx)/sqrt(2x^3-9x^2+12x+4) then

If f(x) =(e^x)/(1+e^x), I_1=int(f(-a))^(f(a)) xg(x(1-x)dx, and I_2=int_(f(-a))^(f(a)) g(x(1-x))dx, then the value of (I_2)/(I_1) is (a) -1 (b) -2 (c) 2 (d) 1

If y=tan^(-1)((2^x)/(1+2^(2x+1))),t h e n(dy)/(dx)a tx=0 is (a)1 (b) 2 (c) 1n 2 (d) none of these

For x in R and a continuous function f, let I_1=int_(s in^2t)^(1+cos^2t)xf{x(2-x)}dxa n dI_2= int_(sin^2t)^(1+cos^2)xf{x(2-x)}dxdotT h e n(I_1)/(I_2) is -1 (b) 1 (c) 2 (d) 3