The differential equation of the curve `x/(c-1)+y/(c+1)=1` is

Find the differential equation of the family of curves Ax^(2)+By^(2)=1.

The differential equation for the family of curves y = c\ sinx can be given by

From the differential equation of the family curves having equation y=(sin^(-1)x)^(2)+Acos^(-1)x+B .

For each of the differential equations given in (x+y)(dy)/(dx)=1

The solution of the differential equation, dy/dx=(x-y)^(2) , when y(1)=1, is

Integrating factor of the differential equation is (dy)/(dx)=(x+y+1)/(x+1) is

The differential equation representing the family of curves y^2=2c(x+sqrt(c)), where c is a positive parameter, is of (A) order 1 (B) order 2 (C) degree 3 (D) degree 4

If the differential equation representing the family of curves y=C_1 cos 2 x+C_2 cos ^2 x+C_3 sin ^2 x+C_4 is lambda y^(prime)=y^(prime prime) tan2 x , then lambda is

The solution of the differential equation x^2(dy)/(dx)cos(1/x)-ysin(1/x)=-1, where y->-1 as x->oo is