The equation of motion is given by`s(t)=2t^3-6t^2+6` At what time, the velocity and accelerations are zero?

A particle moves so that the distance moved is according to the law s(t)=t^3/3-t^2+3 . At what time the velocity and acceleration are zero respectively?

A particle moves so that the distance moved is according to the law s(t)=(t^(3))/(3)-t^(2)+3 . At what time the velocity and acceleration are zero respectively ?

The distance in meters described by a car in time t seconds is given by s = 4t^(3) - 3t^(2) + 6t -1 . Determine the velocity and acceleration when (i) t = 0, (ii) t =2 seconds.

If s = t^(3) - 4t^(2) + 7 the velocity when the acceleration is zero is

If position of a particle at instant t is given by x=3t^(2) , find the velocity and acceleration of the particle.

The equation of motion is given by s=10t^2+60t , where s is displacement in kilometre and t is time in hour. Find the initial velocity.

The equation of motion is given by s=10t^2+60t , where s is displacement in kilometre and t is time in hour. Find the velocity and acceleration at any point.

The equation of motion is given by s=10t^2+60t , where s is displacement in kilometre and t is time in hour. Find the velocity after 1 hour.

The equation of motion is given by s=10t^(2)+60t . Where s is displacement is kilometre and t is time in hour find Initial velocity.