Home
Class 11
MATHS
A rod of length k slides in a vertical p...

A rod of length `k` slides in a vertical plane, its ends touching the coordinate axes. Prove that the locus of the foot of the perpendicular from the origin to the rod is `(x^2+y^2)^3=k^2x^2y^2dot`

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the coordinates of the foot of the perpendicular P from the origin to the plane 2x-3y+4z-6=0

The locus of the foot of perpendicular from the forcus on any tangent to y^(2) = 4ax is

The locus of the foot of the perpendicular from the origin on each member of the family (4a+ 3)x - (a+ 1)y -(2a+1)=0

the locus of the foot of perpendicular drawn from the centre of the ellipse x^2+3y^2=6 on any point:

A plane passes through a fixed point (a ,b ,c)dot Show that the locus of the foot of the perpendicular to it from the origin is the sphere x^2+y^2+z^2-a x-b y-c z=0.

The coordinates of the foot of the perpendicular from the point (3,-1,11) on the line x/2=(y-2)/3=(z-3)/4

Find the length and the foot of the perpendicular from the point (7,14 ,5) to the plane 2x+4y-z=2.

Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1.

Find the coordinates of the foot of the perpendicular and length of the perpendicular from the point (4,3,2) to the plane x + 2y + 3z = 2.