If the area of the triangle formed by the points `(2a ,b)(a+b ,2b+a),` and `(2b ,2a)` is `2qdotu n i t s ,` then the area of the triangle whose vertices are `(a+b ,a-b),(3b-a ,b+3a),` and `(3a-b ,3b-a)` will be_____

Find the area of the triangle whose vertices are A(3, -1,2) ,B(1, - 1, 3) and C(4, - 3 , 1)

Find the area of the triangle whose vertices are A (3,-1,2), B(1,-1,-3) and C(4,-3,1).

Find the area of the triangle formed by the points A(0, – 1), B(– 2, 6) and C(– 3, – 5)

The area of the triangle whose vertices are A(1,-1,2),B(2,1-1)C(3,-1,2) is …….

Find the area of the triangle with vertices A(1,1,2)B(2,3,5) and C(1,5,5).

The area of the triangle with vertices at the points (a, b + c), (b, c + a) and (c, a + b) is

Find the area of a triangle having vertices A(3,2),B(11 ,8), and C(8,12)dot

If the extremities of the base of an isosceles triangle are the points (2a ,0) and (0, a), and the equation of one of the side is x=2a , then the area of the triangle is (a) 5a^2s qdotu n i t s (b) (5a^2)/2s qdotu n i t s (c) (25 a^2)/2s qdotu n i t s (d) none of these

Using the method of integration find the area of the triangle ABC, coordinates of whose vertices are A(2, 0) , B (4, 5) and C(6, 3).