The equation of a straight line passing through the point (2,3) and inclined at an angle of `"tan"^(-1)(1//2)` with the line y+2x=5 is

The equation of a straight line passing through the point (2, 3) and inclined at an angle of tan^(-1)(1/2) with the line y+2x=5 y=3 (b) x=2 3x+4y-18=0 (d) 4x+3y-17=0

Find the equation of the lines passing through the point (1,1) and (-2,3)

Find the equations of the lines which pass through the origin and are inclined at an angle tan^(-1)m to the line y=m x+cdot

Find the equation of a straight line passing through the point (-5,4) and which cuts off an intercept of sqrt(2) units between the lines x+y+1=0 and x+y-1=0.

Write the equation of the line passing through the point (1,-1) and parallel to the line x+3y -4=0

Find the equation of a straight line passing through the point P(-5, 2) and parallel to the line joining the points Q(3, -2) and R(-5, 4) .

Find the slope of the straight line passing through the points (5,7) and (7,5). Also find the angle of inclination of the line with the x-axis .