In `Delta ABC` , vertex A is (1,2). If the internal angle bisector of `angle B` is 2x-y+10=0 and the perpendicular bisector of AC is y=x, then find the equation of BC.

In triangleABC , vertex A is (1, 2). If the internal angle bisector of angle B is 2x- y+10=0 and the perpendicular bisector of AC is y = x, then find the equation of BC

Line x + 2y - 8 = 0 is the perpendicular bisector of AB. If B = (3, 5) the A is

Let A B C be a triangle. Let A be the point (1,2),y=x be the perpendicular bisector of A B , and x-2y+1=0 be the angle bisector of /_C . If the equation of B C is given by a x+b y-5=0 , then the value of a+b is (a) 1 (b) 2 (c) 3 (d) 4

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

The vertices of a triangle are A(-1,-7),B(5,1)a n dC(1,4)dot If the internal angle bisector of /_B meets the side A C in D , then find the length A Ddot

Let A,B,C be angles of triangles with vertex A -= (4,-1) and internal angular bisectors of angles B and C be x - 1 = 0 and x - y - 1 = 0 respectively. If A,B,C are angles of triangle at vertices A,B,C respectively then cot ((B)/(2))cot .((C)/(2)) =

In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1, 2) and (2. 1). If the equation of the line AB is y= 2x, then the equation of the line AC is

The vertex A of DeltaABC is (3,-1). The equation of median BE and angle bisector CF are x-4y+10=0 and 6x+10y-59=0, respectively. Equation of AC is