Two sides of a rhombus ABCD are parallel to the lines y = x + 2 and y = 7x + 3 If the diagonals of the rhombus intersect at the point (1, 2) and the vertex A is on the y-axis, then vertex A can be

The sides of a rhombus are parallel to the lines x+y-1=0 and 7x-y-5=0. It is given that the diagonals of the rhombus intersect at (1, 3) and one vertex, A of the rhombus lies on the line y=2x . Then the coordinates of vertex A are (8/5,(16)/5) (b) (7/(15),(14)/(15)) (6/5,(12)/5) (d) (4/(15),8/(15))

Two sides of a rhombus are along the lines, x-y+1=0 and 7x-y-5=0 . If its diagonals intersect at (-1,-2) , then which one of the following is a vertex of this rhombus ? (1) (-3,-9) (2) (-3,-8) (3) (1/3,-8/3) (4) (-(10)/3,-7/3)

If (a, b) be an end of a diagonal of a square and the other diagonal has the equation x-y=a , then another vertex of the square can be

The point of intersection of the curves y^(2) = 4x and the line y = x is

If the equation of the base opposite to the vertex (2,3) of a equilateral triangle is x+y=2, then the length of a side is

If the two sides of rhombus are x+2y+2=0 and 2x+y-3=0, then find the slope of the longer diagonal.

Two sides of a rhombus lying in the first quadrant are given by 3x-4y=0a n d12 x-5y=0 . If the length of the longer diagonal is 12, then find the equations of the other two sides of the rhombus.

The diagonals of a parallelogram PQRS are along the lines x+3y =4 and 6x-2y = 7, Then PQRS must be :

The tangents to the curve y = (x - 2)^(2) - 1 at its points of intersectio with the line x - y = 3, intersect at the point