Distance of origin from the line `(1+sqrt3)y+(1-sqrt3)x=10` along the line `y=sqrt3x+k`

The distance of the point (1, 2) from the line x + y + 5 = 0 measured along the line parallel to 3x - y = 7 is equal to

Distance of point (2,3) from the line 2x-3y+9=0 along x-y+1=0

Locate sqrt3 on number line

The equation of the lines passing through the point (1,0) and at a distance (sqrt(3))/2 from the origin is (a) sqrt(3)x+y-sqrt(3) =0 (b) x+sqrt(3)y-sqrt(3)=0 (c) sqrt(3)x-y-sqrt(3)=0 (d) x-sqrt(3)y-sqrt(3)=0

The locus of the point of intersection of the lines sqrt3 x- y-4sqrt3 t= 0 & sqrt3 tx +ty-4 sqrt3=0 (where t is a parameter) is a hyperbola whose eccentricity is:

The area of the triangle formed by joining the origin to the point of intersection of the line xsqrt(5)+2y=3sqrt(5) and the circle x^2+y^2=10 is (a)3 (b) 4 (c) 5 (d) 6

Find the slope and y intercept of sqrt(3)x +(1-sqrt3)y=3 .

The locus of the point (sqrt(3h),(sqrt(3)k+2)) if it lies on the line x-y-1=0 is straight line (b) a circle a parabola (d) none of these