In `triangle ABC, ` the coordinates of the vertex A are , `(4,-1)` and lines `x - y - 1 = 0 and 2x - y = 3 ` are the internal bisectors of angles B and C . Then the radius of the circles of triangle AbC is

In A B C , the coordinates of the vertex A are (4,-1) , and lines x-y-1=0 and 2x-y=3 are the internal bisectors of angles Ba n dC . Then, the radius of the encircle of triangle A B C is 4/(sqrt(5)) (b) 3/(sqrt(5)) (c) 6/(sqrt(5)) (d) 7/(sqrt(5))

In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1, 2) and (2. 1). If the equation of the line AB is y= 2x, then the equation of the line AC is

The vertices of a triangle are A(3, 7), B(3, 4) and C(5, 4). The equation of the bisector of the angle /_ABC is

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is

In triangleABC , vertex A is (1, 2). If the internal angle bisector of angle B is 2x- y+10=0 and the perpendicular bisector of AC is y = x, then find the equation of BC

Let A,B,C be angles of triangles with vertex A -= (4,-1) and internal angular bisectors of angles B and C be x - 1 = 0 and x - y - 1 = 0 respectively. If A,B,C are angles of triangle at vertices A,B,C respectively then cot ((B)/(2))cot .((C)/(2)) =

The sides of a triangle ABC lie on the lines 3x + 4y = 0, 4x +3y =0 and x =3 . Let (h, k) be the centre of the circle inscribed in triangleABC . The value of (h+ k) equals

A triangle ABC is formed by the points A(2, 3), B(-2, -3), C(4, -3). What is the point of intersection of the side BC and the bisector of angle A?

If the plane x/2+y/3+z/6=1 cuts the axes of coordinates at points, A ,B ," and "C , then find the area of the triangle A B C

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0