The equation of the normal to the curve`y=x^3`, at (1,1) is

The equation of the normal to the curve theta = (1)/(t) " at " (-3, (-1)/(3)) is:

Find the equation of the normals to the curve y = x^(3) + 2x + 6 which are parallel to the line x + 14y + 4 = 0.

Find the equation of the normal to the curve y=(1+x)^y+sin^(-1)(sin^2x) at x=0.

Find the equation of the normal to the curve x^3+y^3=8x y at the point where it meets the curve y^2=4x other than the origin.

Find the equation of the normal to the curve x^(2) = 4y which passes through the point (1, 2).

Find the equations of tangent and normal to the curve y=x^(2) - 2x -3 at the point (2, 3)

Find the equation of tangent and normal to the curve y = x^(2) + 3x + 2 at (0, 2)

Equation of the normal to the curve y=2x^(2)+3sinx at x = 0 is

Find the equations of tangent and normal to the curve y=x^(2)+3x-2 at the point (1, 2). .