If one end of the a diameter of the circle `2x^2+2y^2-4x-8y+2=0` is (3, 2), then find the other end of the diameter.

If one end of a diameter of a circle 2x^2 + 2y^2 - 4x - 8y + 2 = 0 is (3,2), then the other end is

The line x+3y=0 is a diameter of the circle x^2+y^2-6x+2y=0

If the coordinates at one end of a diameter of the circle x^(2) + y^(2) - 8x -4y + c=0 are (11,2) the coordinates of the other end are

If the line x+2b y+7=0 is a diameter of the circle x^2+y^2-6x+2y=0 , then find the value of b

If one end of a diameter of a circle is (3,5) and the centre is (2,3) then the other end of the diameter is

If one of the diameters of the circle x^2+y^2-2 x-6 y+6 =0 is a chord to the circle with centre at (2,1) then the radius of the circle is equal to.

The centre of a cirlce is (-4,2) . If one end of the diameter of the circle is (-3,7) tehn find the other end.

The centre of a circle is at (-6,4). If one end of a diameter of the circle is at the origin then the other ends is ......

If the coordinate of one end of a diameter of a circle is (3,4) and the coordinates of its centre is (-3,2) then the coordinate of the other end of the diameter is .