The centre of a circle passing through (0,0), (1,0) and touching the CircIe `x^2+y^2=9` is a. `(1/2,sqrt2)` b. `(1/2,3/sqrt2)` c. `(3/2,1/sqrt2)` d. `(1/2,-1/sqrt2)`

A circle passes through (0,0) and (1, 0) and touches the circle x^2 + y^2 = 9 then the centre of circle is -

The eccentricity of the locus of point (3h+2,k), where (h , k) lies on the circle x^2+y^2=1 , is 1/3 (b) (sqrt(2))/3 (c) (2sqrt(2))/3 (d) 1/(sqrt(3))

Find the equation of the normal to the circle x^(2)+y^(2)=9 at the point (1//sqrt(2), 1// sqrt(2)) .

The common chord of the circle x^2+y^2+6x+8y-7=0 and a circle passing through the origin and touching the line y=x always passes through the point. (-1/2,1/2) (b) (1, 1) (1/2,1/2) (d) none of these

The equation of a circle of radius 1 touching the circles x^2+y^2-2|x|=0 is (a) x^2+y^2+2sqrt(2)x+1=0 (b) x^2+y^2-2sqrt(3)y+2=0 (c) x^2+y^2+2sqrt(3)y+2=0 (d) x^2+y^2-2sqrt(2)+1=0

Radius of the circle that passes through the origin and touches the parabola y^2=4a x at the point (a ,2a) is (a) 5/(sqrt(2))a (b) 2sqrt(2)a (c) sqrt(5/2)a (d) 3/(sqrt(2))a

The incenter of the triangle with vertices (1,sqrt(3)),(0,0), and (2,0) is (a) (1,(sqrt(3))/2) (b) (2/3,1/(sqrt(3))) (c) (2/3,(sqrt(3))/2) (d) (1,1/(sqrt(3)))

Find the equation of the normal to the circle x^2+y^2=9 at the point (1/(sqrt(2)),1/(sqrt(2)))

The equation of chord AB of the circle x^2+y^2=r^2 passing through the point P(1,1) such that (PB)/(PA)=(sqrt2+r)/(sqrt2-r) , (0ltrltsqrt(2))

The equation of four circles are (x+-a)^2+(y+-a)^2=a^2 . The radius of a circle touching all the four circles is (a) (sqrt(2)+2)a (b) 2sqrt(2)a (c) (sqrt(2)+1)a (d) (2+sqrt(2))a