Home
Class 11
MATHS
Two circle x^2+y^2=6 and x^2+y^2-6x+8=0 ...

Two circle `x^2+y^2=6` and `x^2+y^2-6x+8=0` are given. Then the equation of the circle through their points of intersection and the point (1, 1) is (a) `x^2+y^2-6x+4=0` (b)`x^2+y^2-3x+1=0` (c) `x^2+y^2-4y+2=0` (d)none of these

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the line passing through the points of intersection of the circles 3x^2 +3y^2-2x + 12y-9=0 and x^2+y^2+6x+2y-15=0 is

Find the equation of the circle passing throught (1,1) and the points of intersection of the circles x^(2)+y^(2)+13x-3y=0 and 2x^(2)+2y^(2)+4x-7y-25=0

Show that the equation of the circle passing through (1, 1) and the points of intersection of the circles x^2+y^2+13 x-3 y=0 and 2x^2+2y^2+4x-7y-25=0 is 4x^2+4y^2+30 x-13 y-25=0.

The equation of the circle passing through the point of intersection of the circles x^2+y^2-4x-2y=8 and x^2+y^2-2x-4y=8 and the point (-1,4) is (a) x^2+y^2+4x+4y-8=0 (b) x^2+y^2-3x+4y+8=0 (c) x^2+y^2+x+y=0 (d) x^2+y^2-3x-3y-8=0

Find the point of intersection of the circle x^2+y^2-3x-4y+2=0 with the x-axis.

The locus of the image of the point (2,3) in the line (x-2y+3)+lambda(2x-3y+4)=0 is (lambda in R) (a) x^2+y^2-3x-4y-4=0 (b) 2x^2+3y^2+2x+4y-7=0 (c) x^2+y^2-2x-4y+4=0 (d) none of these

The equation of the circle which has normals (x-1).(y-2)=0 and a tangent 3x+4y=6 is (a) x^2+y^2-2x-4y+4=0 (b) x^2+y^2-2x-4y+5=0 (c) x^2+y^2=5 (d) (x-3)^2+(y-4)^2=5

The circles x^2+y^2-12 x-12 y=0 and x^2+y^2+6x+6y=0. touch each other externally touch each other internally intersect at two points none of these

Find the locus of the point of intersection of the perpendicular tangents of the curve y^2+4y-6x-2=0 .

The equation of the cirele which passes through the point (1, 1) and touches the circle x^2+y^2+4x-6y-3=0 at the point (2, 3) on it is