The acute angle between the line `3x-4y=5` and the circle `x^2+y^2-4x+2y-4=0` is `theta` . Then `9costheta=`

The angle between the line 3x-2y=0 and 2x+3y+5=0 is ………………….. .

Find the acute angle between the following lines. 2x=3y=-zand6x=-y=-4z

Find the image of the circle x^2+y^2-2x+4y-4=0 in the line 2x-3y+5=0

Find the angle between the lines x-3y-4=0,4y-z+5=0a n dx+3y-11=0,2y=z+6=0.

Find the angle between the lines x-3y-4=0,4y-z+5=0a n dx+3y-11=0,2y=z+6=0.

If theta is the angle between the lines given by the equation 6x^2+5x y-4y^2+7x+13 y-3=0 , then find the equation of the line passing through the point of intersection of these lines and making an angle theta with the positive x-axis.

A right angled isosceles triangle is inscribed in the circle x^2 + y^2 -4x - 2y - 4 = 0 then length of its side is

theta is acute angle between the lines x^(2)-xy-6y^(2)=0 , then (2costheta+3sintheta)/(4sintheta+5costheta) is