If the vertex of the parabola is `(3,2)` and directrix is `3x+4y-(19)/7=0` , then find the focus of the parabola.

Find the vertex of the parabola x^2=2(2x+y)

The vertex of the parabola x^(2)=8y-1 is :

Find the equation of the parabola. Focus (4,0) and directrix x=-4.

The vertex of the parabola y^2 + 4x = 0 is

If the focus of a parabola is (2, 3) and its latus rectum is 8, then find the locus of the vertex of the parabola.

Find the equation of parabola whose focus is (0,1) and the directrix is x+2=0. Also find the vertex of the parabola.

Find the equation of the parabola with focus (2,0) and directrix x=-2 .

Find the equation of the parabola with focus (-1,0) and directrix x = 1.

If the vertex of a parabola is the point (-3,0) and the directrix is the line x+5=0 , then find its equation.

The vertex of the parabola y^2 = 4x + 4y is