If `(a ,b)` is the midpoint of a chord passing through the vertex of the parabola `y^2=4x,` then prove that `2a=b^2`

If (a ,b) is the midpoint of a chord passing through the vertex of the parabola y^2=4(x+1), then prove that 2(a+1)=b^2

If (a , b) is the midpoint of a chord passing through the vertex of the parabola y^2=4x , then a=2b (b) a^2=2b a^2=2b (d) 2a=b^2

The vertex of the parabola y^2 = 4x + 4y is

The vertex of the parabola y^2 + 4x = 0 is

Find the vertex of the parabola x^2=2(2x+y)

The vertex of the parabola x^(2)=8y-1 is :

The locus of the middle points of the focal chords of the parabola, y^2=4x is:

Find the length of normal chord which subtends an angle of 90^0 at the vertex of the parabola y^2=4xdot

Find the locus of the midpoint of chords of the parabola y^2=4a x that pass through the point (3a ,a)dot