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The volume of a tetrahedron formed by ...

The volume of a tetrahedron formed by the coterminous edges ` vec a , vec b ,a n d vec c` is 3. Then the volume of the parallelepiped formed by the coterminous edges ` vec a+ vec b , vec b+ vec ca n d vec c+ vec a` is a.`6` b. `18` c. `36` d. 9

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Volume of tetrahedron= `1/6*[veca vecb vecc]=3`
Hence, `[vec(a) vec(b) vec(c)]=18`
Volume of parallelopiped=` [vec(a+b) vec(b+c) vec(c+a)]`
= `2[veca vecb vecc]`
=2*18=36.
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