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The angle between the tangents to the cu...

The angle between the tangents to the curve `y=x^2-5x+6` at the point (2, 0) and (3, 0) is `pi/2` (b) `pi/3` (c) `pi` (d) `pi/4`

A

`(pi)/(2)`

B

`(pi)/(3)`

C

`(pi)/(6)`

D

`(pi)/(4)`

Text Solution

Verified by Experts

(1) `(dy)/(dx)=2x-5`
`:." "m_(1)=((dy)/(dx))_((2","0))=4-5=-1`
`and" "m_(2)=((dy)/(dx))_((3","0))=6-5=1`
`:." "m_(1)m_(2)=-1`
Therefore, the angle between the tangents is `pi//2`.
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