The extremities of latus rectum of a parabola are (1, 1) and `(1,-1)` . Then the equation of the parabola can be (a)`y^2=2x-1` (b) `y^2=1-2x` (c)`y^2=2x-3` (d) `y^2=2x-4`

The latus rectum of the parabola y^2 = 11x is of length

The latus rectum of the parabola y^(2)-4x+4y+8=0 is:

The length of latus rectum of the parabola 4y^2 + 2x - 20y + 17 = 0 is

The parametric equation of a parabola is x=t^2+1,y=2t+1. Then find the equation of the directrix.

The vertex of the parabola x^(2)=8y-1 is :

The equation of the latus rectum of y^(2)=4x is….......

If the tangents and normals at the extremities of a focal chord of a parabola intersect at (x_1,y_1) and (x_2,y_2), respectively, then x_1=y^2 (b) x_1=y_1 y_1=y_2 (d) x_2=y_1

The coordinates of the ends of a focal chord of the parabola y^2=4a x are (x_1, y_1) and (x_2, y_2) . Then find the value of x_1x_2+y_1y_2 .

Find the equation of the tangent to the parabola x=y^2+3y+2 having slope 1.

The area of the region bounded by the parabola (y-2)^(2) = x- 1 , the tangent to the parabola at the point (2,3) and the x-axis is