Find the point of intersection of the lines  ` (x-1)/(2)=(y-2)/(3)=(z-3)/(4) ` and  ` (x-4)/(5)=(y-1)/(2)=z ` .

Find the point of intersection of the lines (x-1)/(3)=(y-1)/(-1) = z+2’and (x-4)/(2)=y=(z+1)/(3) .

The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1 and (x+3)/(-36)=(y-3)/2=(z-6)/4 is (A) (21 ,5/3,(10)/3) (B) (2,10 ,4) (C) (-3,3,6) (D) (5,7,-2)

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

Find the equation of the projection of the line (x-1)/2=(y+1)/(-1)=(z-3)/4 on the plane x+2y+z=9.

The equation of the plane which passes through the point of intersection of lines ""(x-1)/3=(y-2)/1=(z-3)/2"","and"(x-3)/1=(y-1)/2=(z-2)/3 and at greatest distance from point (0,0,0) is a. 4x+3y+5z=25 b. 4x+3y=5z=50 c. 3x+4y+5z=49 d. x+7y-5z=2

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.

Show that the lines (x-1)/(4)=(2-y)/(6)=(z-4)/(12) and (x-3)/(-2)=(y-3)/(-2)=(5-z)/(6) are parallel.

Find the equation of a line which passes through the point (1,1,1) and intersects the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x+2)/1=(y-3)/2=(z+1)/4dot

Find the shortest distance between the lines (x-1)/2=(y-2)/3=(z-3)/4 and (x-2)/3=(y-3)/4=(z-5)/5 .

The distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/2=(y+1)/4=(z-2)/12 and the plane x-y+z=5 is