Find the distance of the point `(1,0,-3)` from the plane `x-y-z=9` measured parallel to the line `(x-2)/2=(y+2)/2=(z-6)/(-6)dot`

The distance of the point (2,1,-1) from the plane x-2y+4z=9 is

The distance of the point (1,-2,3) from the plane x-y+z-5=0 , measured parallel to the line x/2=y/3=(z-1)/-6 is equal to

Find the distance of the point P(3,8,2) from the line 1/2(x-1)=1/4(y-3)=1/3(z-2) measured parallel to the plane 3x+2y-2z+15=0.

Find the distance of the plane 2x-y-2z-9=0 from the origin.

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.

Find the distance of the point (-2,3,"\ "-4) from the line ("x"+2)/3=(2"y"+3)/4=(3"z"+4)/5 measured parallel to the plane 4"x"+12"y"-3"z"+1=0.

If the plane 2x-y+z=0 is parallel to the line (2x-1)/2=(2-y)/2 =(z+1)/a , then the value of a is

Find the equation of the plane through the points (1,0,-1),(3,2,2) and parallel to the line (x-1)/1=(y-1)/(-2)=(z-2)/3 .

Find the equation of the plane passing through the points (1,0,-1)a n d(3,2,2) and parallel to the line x-1=(1-y)/2=(z-2)/3dot

The distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/2=(y+1)/4=(z-2)/12 and the plane x-y+z=5 is