Find the distance of the point `(-1,-5,-10)` from the point of intersection of the line `(x-2)/3=(y+1)/4=(z-2)/(12)` and plane `x-y+z=5.`

The distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/2=(y+1)/4=(z-2)/12 and the plane x-y+z=5 is

Find the distance of the point (1,0,-3) from the plane x-y-z=9 measured parallel to the line (x-2)/2=(y+2)/2=(z-6)/(-6)dot

The distance of the point (2,1,-1) from the plane x-2y+4z=9 is

Find the point of intersection of the lines (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2)=z .

Find the point of intersection of the lines (x-1)/(3)=(y-1)/(-1) = z+2’and (x-4)/(2)=y=(z+1)/(3) .

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

Find the distance of the point (-1, 1) from the line 12 (x + 6) = 5 (y - 2) .

Find the distance of the point (5,-5, -10) from the point of intersection of a straight line passing through the points A(4, 1, 2) and B(7, 5, 4) with the plane x-y+z=5.