Home
Class 11
MATHS
Find the locus of he foot fo the perpen...

Find the locus of he foot fo the perpendicular draw from the centre upon any tangent to the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1.

The locus of the foot of perpendicular from the forcus on any tangent to y^(2) = 4ax is

Locus of perpendicular from center upon normal to the hyperbola (x^(2))/(a^(2)) -(y^(2))/(b^(2)) =1 is

the locus of the foot of perpendicular drawn from the centre of the ellipse x^2+3y^2=6 on any point:

The locus of foot of the perpendiculars drawn from the vertex on a variable tangent to the parabola y^2 = 4ax is

Find the foot of the perpendicular from the point (2,4) upon x+y=1.

Statement 1 : For the ellipse (x^2)/5+(y^2)/3=1 , the product of the perpendiculars drawn from the foci on any tangent is 3. Statement 2 : For the ellipse (x^2)/5+(y^2)/3=1 , the foot of the perpendiculars drawn from the foci on any tangent lies on the circle x^2+y^2=5 which is an auxiliary circle of the ellipse.

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (x^2-y^2)=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

Locus of the feet of the perpendiculars drawn from either foci on a variable tangent to the hyperbola 16y^2 -9 x^2 = 1 is

Find the length and the foot of the perpendicular from the point (7,14 ,5) to the plane 2x+4y-z=2.