`P` is a variable on the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` with AA' as the major axis. Find the maximum area of triangle `A P A '`

Find the area of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 .

If the area of the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 is 4pi , then find the maximum area of rectangle inscribed in the ellipse.

Find the maximum area of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 which touches the line y=3x+2.

P and Q are the foci of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 and B is an end of the minor axis. If P B Q is an equilateral triangle, then the eccentricity of the ellipse is

The area enclosed by the ellipse (x^(2))/(a^(2)) + (y^(2))/(b^(2)) = 1 is equal to

Extremities of the latera recta of the ellipses (x^2)/(a^2)+(y^2)/(b^2)=1(a > b) having a given major axis 2a lies on

The maximum area of an isosceles triangle inscribed in the ellipse (x^2)/(a^2) + (y^2)/(b^2) = 1 with the vertex at one end of the major axis is

If P(alpha,beta) is a point on the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 with foci Sa n dS ' and eccentricity e , then prove that the area of S P S ' is basqrt(a^2-alpha^2)

Volume of solid obtained by revolving the area of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 about major and minor axes are in tha ratio……